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 4=5 ???? 
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Post Re: 4=5 ????
Charliee wrote:
toate exercitiile de acest gen tin de limita spre infinit, adica oricare ar fi un nr x/ 0 = lim inf


]scuze ca te contrazic, da nu cred ca ce ai spus u este corect, ca o limita sa tinda la infinit, x nostru tr sa ia valori de la 1 pana la infinit, iar in cazul; iar la noi X este decat un nr, nu o infinitate

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03 Dec 2008, 13:38
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Post Re: 4=5 ????
si pe forumu de cs am ajuns sa vad de matematica sa ma crucesc nu alta :X baieti harnici nu gluma :X

-- Mon Dec 08, 2008 07:12 --

dReam wrote:
(B-A)^2 nu e egal cu B^2-2AB+A^2 / -A^2
si de aici pleca tot

:idea:
mai da pe la scoala tatiii mai lasa cs1.6.exe deoparte ! #-turkey

A=4, B=5, C=1 .

C=B-A / (B-A)
C(B-A)=(B-A)^2
CB-CA=B^2-2AB+A^2 / -A^2
CB-CA-A^2=B^2-2AB / +A^2 <======= ny vad unde ai adaugat A^2 in ecuatia urmatoare! ci doar ai despicat -2ab
AB+CB-CA-A^2=B^2-AB / -CB
AB-CA-A^2=B^2-CB-AB
A(B-C-A)=B(B-C-A)
inlocuieste acuma cu cifre pentru a vedea semnu:
A=4, B=5, C=1 .
deci avem asa 4(5-1-4)=5(5-1-4) parantezele sunt egale cu zero si deci 4 nu mai este egal cu 5 ;) doooh

fii mai atent si du-te pe la scoala ;)
A=B => 4=5 #

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08 Dec 2008, 07:44
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