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 4=5 ???? 
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Post 4=5 ????
A=4, B=5, C=1 .

C=B-A / (B-A)
C(B-A)=(B-A)^2
CB-CA=B^2-2AB+A^2 / -A^2
CB-CA-A^2=B^2-2AB / +A^2
AB+CB-CA-A^2=B^2-AB / -CB
AB-CA-A^2=B^2-CB-AB
A(B-C-A)=B(B-C-A)

A=B => 4=5 :lol:

Ce este gresit in ecuatie :idea: . Aveti 1 saptamana la dispozitie :P . Bafta #-minfo


P.S. X^2 inseamna X la puterea a 2

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Jucand acest joc am invatat ca daca esti mic poti face lucruri mari, punand suflet in lucruri mari poti face sa fie gigantice ... insa am mai invatat ca fara prieteni poti sa te prabusesti de acolo imediat...



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30 Nov 2008, 09:28
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Post Re: 4=5 ????
(B-A)^2 nu e egal cu B^2-2AB+A^2 / -A^2
si de aici pleca tot

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30 Nov 2008, 13:11
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Post Re: 4=5 ????
dReam wrote:
(B-A)^2 nu e egal cu B^2-2AB+A^2 / -A^2
si de aici pleca tot


ba da
*(a+b)^2 = a^2+2ab+b2
*(a-b)^2 = a^2-2ab+b2

Binomul lui Newton !

Off Topic. Cineva nu a dat pe la scoala #-yahoo

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Jucand acest joc am invatat ca daca esti mic poti face lucruri mari, punand suflet in lucruri mari poti face sa fie gigantice ... insa am mai invatat ca fara prieteni poti sa te prabusesti de acolo imediat...



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* To understand man you must be a man, but to understand girls, you must be a GOD! (maybe)
* Beţia e nebunie cu voia.


30 Nov 2008, 13:44
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Post Re: 4=5 ????
B-C-A = 0
DECI A*0 = B*0

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30 Nov 2008, 15:10
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Post Re: 4=5 ????
P!t!C wrote:
B-C-A = 0
DECI A*0 = B*0


Asa, ce e cu asta ??

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Jucand acest joc am invatat ca daca esti mic poti face lucruri mari, punand suflet in lucruri mari poti face sa fie gigantice ... insa am mai invatat ca fara prieteni poti sa te prabusesti de acolo imediat...



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* To understand man you must be a man, but to understand girls, you must be a GOD! (maybe)
* Beţia e nebunie cu voia.


30 Nov 2008, 16:08
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Post Re: 4=5 ????
ciubey_devil wrote:
P!t!C wrote:
B-C-A = 0
DECI A*0 = B*0


Asa, ce e cu asta ??

ha ha mai bine taceai ciubey .. ahahah cica ce e cu asta pai daca
B-C-A = 0 =>
A(B-C-A)= A*0 =0
B(B-C-A)= B*0 =0
=> B nu este egal cu A

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30 Nov 2008, 16:15
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Post Re: 4=5 ????
Skynet wrote:
ha ha mai bine taceai ciubey .. ahahah cica ce e cu asta pai daca
B-C-A = 0 =>
A(B-C-A)= A*0 =0
B(B-C-A)= B*0 =0
=> B nu este egal cu A


Nu asta e raspunsul, voi kiar nu sunteti atenti la ora de matematica...., defapt nu prea inteleg ce vrei u sa demonstrezi ???
Daca nu iti dedeam numerele si iti spuneam ca A!=B!=C cu proprietatea ca C=B-A, ce raspuns dadeai ??, oricum esti pe aproape !

Oricum, uite solutia, presupun ca asta vroiai sa spui :X


Code:
B - C - A = 5 - 4 - 1 = 0

A x ( B - C - A ) = B x ( B - C - A )

Deci A x ( B - C - A ) / ( B - C - A) e acelasi lucru ca A x ( B - C - A ) / 0

Oricine stie ca x / 0 nu are solutii

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Jucand acest joc am invatat ca daca esti mic poti face lucruri mari, punand suflet in lucruri mari poti face sa fie gigantice ... insa am mai invatat ca fara prieteni poti sa te prabusesti de acolo imediat...



OFFTOPIC:
* To understand man you must be a man, but to understand girls, you must be a GOD! (maybe)
* Beţia e nebunie cu voia.


Last edited by Ciubey on 30 Nov 2008, 17:00, edited 2 times in total.

30 Nov 2008, 16:45
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Post Re: 4=5 ????
A(B-C-A)=B(B-C-A)

B-C-A = 0 => a*0 =b*0 => 0 cu 0 nu se simplifica pt ca 0/0 nu se poate:


A=B(B-C-A)/(B-C-A)

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30 Nov 2008, 17:00
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Post Re: 4=5 ????
daca imi dadea profesoru ceva asemanator la scoala..sau daca scria asa ceva pe tabla..il scuipam intre ochii si ii spuneam sa se apuce de limba romana nu de matematica :P :P

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30 Nov 2008, 23:15
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Post Re: 4=5 ????
ciubey_devil wrote:
Nu asta e raspunsul, voi kiar nu sunteti atenti la ora de matematica...., defapt nu prea inteleg ce vrei u sa demonstrezi ???
Daca nu iti dedeam numerele si iti spuneam ca A!=B!=C cu proprietatea ca C=B-A, ce raspuns dadeai ??, oricum esti pe aproape !
Oricum, uite solutia, presupun ca asta vroiai sa spui :X

Daca tu imi ziceai ca C=B-A => ca B=C+A => B-C+A=0
Mai ciumpalacule ia scoate-mi si mie forma trigonometrica dintr-un nr imaginar sa zicem Z=-i( se presupune ca toti ati trecut de clasa a X-a)

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01 Dec 2008, 09:58
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Post Re: 4=5 ????
Skynet wrote:
corect e B-C-A=0
Mai ciumpalacule ia scoate-mi si mie forma trigonometrica dintr-un nr imaginar sa zicem Z=-i( se presupune ca toti ati trecut de clasa a X-a)


Z=-i => a=0, b=-1
Z=r(cos t + i sin t) (1)

r=|Z|=SQRT(a^2+b^2)=>r=1
cos t = a / r => 0 | (2)
sin t = b / r => -1 | (3)

(2)(3)=>t= 3 pi / 2 => Z=(cos 3pi/2+ i sin 3 pi /2)

Desen=Image

uite ca ti-am facut si tema #-tease

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Jucand acest joc am invatat ca daca esti mic poti face lucruri mari, punand suflet in lucruri mari poti face sa fie gigantice ... insa am mai invatat ca fara prieteni poti sa te prabusesti de acolo imediat...



OFFTOPIC:
* To understand man you must be a man, but to understand girls, you must be a GOD! (maybe)
* Beţia e nebunie cu voia.


Last edited by Ciubey on 01 Dec 2008, 12:00, edited 3 times in total.

01 Dec 2008, 11:02
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Post Re: 4=5 ????
nup nu e bine,pt ca tu ai omis un lucru : cadranul
oricum hai sa nu ne mai dam noi einstenieniisi si sa lasam matematica #-drink #-beer

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01 Dec 2008, 11:19
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Post Re: 4=5 ????
Skynet wrote:
nup nu e bine,pt ca tu ai omis un lucru : cadranul
oricum hai sa nu ne mai dam noi einstenieniisi si sa lasam matematica #-drink #-beer


e nu-i bine, taci fa ca e bine, si daca te referi la Cazurile acelea cu a=0 si b<0, iar atunci z=-b(cost t + i sin t), e aceasi kestie cu ce am facut eu, numai ca eu am facut mai generel, nu pe cazuri particulare

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Jucand acest joc am invatat ca daca esti mic poti face lucruri mari, punand suflet in lucruri mari poti face sa fie gigantice ... insa am mai invatat ca fara prieteni poti sa te prabusesti de acolo imediat...



OFFTOPIC:
* To understand man you must be a man, but to understand girls, you must be a GOD! (maybe)
* Beţia e nebunie cu voia.


01 Dec 2008, 12:46
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Post Re: 4=5 ????
de azi inainte skynet e dascalu si ciubey profesoru..v-am botezat gata :P :P :P

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01 Dec 2008, 20:23
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Post Re: 4=5 ????
toate exercitiile de acest gen tin de limita spre infinit, adica oricare ar fi un nr x/ 0 = lim inf


03 Dec 2008, 02:06
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